Possible 4-digit combinations of numbers 0, 5, and 8?
Just give me ideas. I locked myself out of my iphone and i can't restore my phone.
Any 4 digit passcodes containing those numbers are a possibility.
There are 3^4 = 81 such combinations starting with 0000.
Mathematically speaking, you would have to attempt 81 different passcodes, which I'm sure would not be allowed on an iPhone. Instead, look at the smudges, and see if one of those digits is smudged more than the others, indicating that perhaps that number is used twice. From that, just remember the feel for he movement while typing it and you would probably get the order.
0058
0085
0580
0850
5800
8500
5008
8005
0508
0805
5080
8050
5508
5580
5805
5085
8055
0855
8550
0558
8505
0585
5058
5850
8805
8850
5088
0588
0885
5880
5808
0858
8085
8580
8508
8058
These are all possible combinations containing all three numbers.
If you want to have all three numbers in the combo and no others you would find
3*3*2*1 = 18 because you can't have the same number more than twice and must have the two other numbers as well in the code
Because all the codes are different when reversed we multiply
18*2 to get 36 possibilities
It should not take more than 2 minutes to enter all the combinations above
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